Filter Out Filename from Full Path String

I'm working on filter job results for some jobs that run robocopy to pull out the currently copying file.  Currently, I've got to the point that I can list the most recent file copying as shown in the sample script below.  Unfortunately, I can't for the life of me figure out how to cut out the data I want from that point.  My results are coming back like this:

C:\WINDOWS\source\I386\SM59W.DL_
C:\WINDOWS\source\I386\SM81W.DL_
C:\WINDOWS\source\I386\SM87W.DL_
C:\WINDOWS\source\I386\SM89W.DL_
C:\WINDOWS\source\I386\SM8AW.DL_

I'm wanting something more like this:

SM59W.DL_
SM81W.DL_
SM87W.DL_
SM89W.DL_
SM8AW.DL_

 

 $job = {robocopy C:\ C:\test /e /L /nS /nc /ndl} 
$jobs = start-job $job 
start-sleep -seconds 3 function Get-LatestResult ($results) 
    { 
    $lresults = $results.length - 1 
    $output = $results[$lresults] 
    return $output 
    }   while (Get-Job -State "Running") { 
$results = (Receive-Job -job $jobs) 
Get-LatestResult $results 
start-sleep -seconds 1 
}

 
I know this one has to be simple, probaby using Trim or something, I figure I can use the last "\" as a filter, but I can't seem to single it out and cut out the rest.

Think I've solved my problem using the string split method.
 

 function Get-LatestResult ($results)
 {
 $lresults = $results.length - 1
 $path = $results[$lresults]
 $path = $path.split("\")
 $lpath = $path.length - 1
 $output = $path[$lpath]
 return $output
 } 

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